Link path with corresponding linked Text

Hello All,

Can any one please help me in getting the source link displayed on the above the linked text.

Regards,

Vijay.

VijayAnne - Mon Apr 10 03:56:46 EDT 2017

Re: Link path with corresponding linked Text
Mathias Mamsch - Mon Apr 10 04:00:19 EDT 2017

Not sure what you mean, but look here:

Maybe it helps, regards, Mathias

Re: Link path with corresponding linked Text
VijayAnne - Mon Apr 10 04:06:03 EDT 2017

Hello Mathias,

Say I have module 1 and 2, and have linked from 1st to 2nd and the linked content should be displayed in module 1 along with the path,

Regards,

Re: Link path with corresponding linked Text
Mathias Mamsch - Mon Apr 10 04:59:28 EDT 2017

VijayAnne - Mon Apr 10 04:06:03 EDT 2017

Hello Mathias,

Say I have module 1 and 2, and have linked from 1st to 2nd and the linked content should be displayed in module 1 along with the path,

Regards,

Yes, so use the code from the above post inside a DXL Layout or DXL attribute column ... and then from inside the link iteration loop you need to

displayRich richText oTarget."Object Text" // Layout DXL

or from attribute DXL:

obj.attrDXLName = richText oTarget."Object Text"

Regarding the "path" I am not sure what you mean? The fullName of the source/target module? Regards, Mathias

Re: Link path with corresponding linked Text
MrNiceGuy - Fri May 12 18:57:49 EDT 2017

Couldn't you use the Analysis Wizard to generate a DXL layout for In-links or Out-links?

Then you can select what attributes you wanted to display from the other module or am I not reading this correctly?